a coffee shop blends 2 kinds of coffee, putting in 2 parts of a $0.33 pound grade to 1 part of a $0.24 grade. if the mixture is changed to 1 part of the $0.33 grade to 2 parts of the less expensive gr

3 weeks ago 12
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Let's define the problem step by step.

Given:

  • Two coffee grades:
    • Grade A: $0.33 per pound
    • Grade B: $0.24 per pound
  • Initial mixture ratio: 2 parts Grade A to 1 part Grade B
  • New mixture ratio: 1 part Grade A to 2 parts Grade B
  • Total weight to blend: 100 pounds

Step 1: Calculate cost per pound of the initial mixture.

  • Total parts in the initial mix = 2 + 1 = 3 parts
  • Weight of Grade A in initial mix per pound = 2/3 pound
  • Weight of Grade B in initial mix per pound = 1/3 pound

Cost of 1 pound of initial blend = (2/3 × $0.33) + (1/3 × $0.24)
= $0.22 + $0.08 = $0.30 per pound

Step 2: Calculate cost per pound of the new mixture.

  • Total parts in the new mix = 1 + 2 = 3 parts
  • Weight of Grade A in new mix per pound = 1/3 pound
  • Weight of Grade B in new mix per pound = 2/3 pound

Cost of 1 pound of new blend = (1/3 × $0.33) + (2/3 × $0.24)
= $0.11 + $0.16 = $0.27 per pound

Step 3: Calculate total cost for 100 pounds in each case.

  • Initial cost = 100 × $0.30 = $30.00
  • New cost = 100 × $0.27 = $27.00

Step 4: Calculate savings.

Savings = Initial cost - New cost = $30.00 - $27.00 = $3.00

Answer:

The shop will save $3.00 by changing the blend ratio on 100 pounds of coffee.