amit and ananthu can do work in 15 days and 25 days respectively. amit started the work and left after 3 days. ananthu took over and completed the work. in how many days was the total work completed?

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To solve this problem, we need to find how many days it took for Amit and Ananthu together to complete the work, given:

  • Amit can complete the work in x days.
  • Ananthu can complete the work in y days.
  • Amit worked for 3 days and then left.
  • Ananthu completed the remaining work.

Step-by-step solution:

Step 1: Define variables

  • Let the total work be 1 unit.
  • Amit's work rate = 1x\frac{1}{x}x1​ work per day.
  • Ananthu's work rate = 1y\frac{1}{y}y1​ work per day.

Step 2: Work done by Amit in 3 days

Work done by Amit in 3 days = 3×1x=3x3\times \frac{1}{x}=\frac{3}{x}3×x1​=x3​

Step 3: Remaining work after Amit leaves

Remaining work = 1−3x=x−3x1-\frac{3}{x}=\frac{x-3}{x}1−x3​=xx−3​

Step 4: Time taken by Ananthu to complete remaining work

Time taken by Ananthu = Remaining workAnanthu’s rate=x−3x1y=(x−3)x×y=y×x−3x\frac{\text{Remaining work}}{\text{Ananthu's rate}}=\frac{\frac{x-3}{x}}{\frac{1}{y}}=\frac{(x-3)}{x}\times y=y\times \frac{x-3}{x}Ananthu’s rateRemaining work​=y1​xx−3​​=x(x−3)​×y=y×xx−3​

Step 5: Total time to complete the work

Total time = Amit's time + Ananthu's time = 3+y×x−3x3+y\times \frac{x-3}{x}3+y×xx−3​

Final formula:

Total time=3+y(x−3)x\boxed{ \text{Total time}=3+\frac{y(x-3)}{x} }Total time=3+xy(x−3)​​

Example:

If Amit can do the work in 6 days and Ananthu in 8 days:

Total time=3+8(6−3)6=3+8×36=3+4=7 days\text{Total time}=3+\frac{8(6-3)}{6}=3+\frac{8\times 3}{6}=3+4=7\text{ days}Total time=3+68(6−3)​=3+68×3​=3+4=7 days

If you provide the exact number of days Amit and Ananthu take individually, I can calculate the exact total time for you!