The balanced chemical equation for the production of ammonia (NH3) from nitrogen (N2) and hydrogen (H2) is: N2+3H2→2NH3N_2+3H_2\rightarrow 2NH_3N2+3H2→2NH3 From this balanced equation, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Given that 30.0 moles of NH3 are produced, the moles of H2 required are calculated using the mole ratio between H2 and NH3 from the balanced equation:
Moles of H2=30.0 moles NH3×3 moles H22 moles NH3=45.0 moles H2\text{Moles of }H_2=30.0\text{ moles NH}_3\times \frac{3\text{ moles }H_2}{2\text{ moles }NH_3}=45.0\text{ moles }H_2Moles of H2=30.0 moles NH3×2 moles NH33 moles H2=45.0 moles H2
Therefore, to produce 30.0 moles of NH3, 45.0 moles of H2 are theoretically needed according to the balanced chemical reaction.
