how many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

3 hours ago 4
Nature

It looks like your query is about forming 3-digit numbers using the digits 2 and 3. I'll assume you want to know:

  • How many 3-digit numbers can be formed using the digits 2 and 3
  • Whether repetition of digits is allowed or not (I'll consider both cases)

Case 1: Repetition Allowed

Digits available: 2, 3
Number of digits in the number: 3 Each digit can be either 2 or 3, so for each of the 3 positions, you have 2 choices. Total numbers = 2 × 2 × 2 = 2³ = 8 The numbers are:
222, 223, 232, 233, 322, 323, 332, 333

Case 2: No Repetition Allowed

Digits available: 2, 3
Number of digits in the number: 3 Since you only have 2 digits (2 and 3), and you need to form a 3-digit number without repeating digits, this is not possible because you don't have enough distinct digits. Total numbers = 0

Summary

Condition| Number of 3-digit numbers formed
---|---
Repetition allowed| 8
No repetition allowed| 0

If you want to include more digits or clarify any other conditions, feel free to ask!