reena took a loan of rs. 1200 with simple interest for as many years as the rate of interest. if she paid rs. 432 as interest at the end of the loan period, what was the rate of interest?

Let's analyze the problem step-by-step.

Given:

• Principal (P) = Rs. 1200
• Simple Interest (SI) = Rs. 432
• Time (T) = Rate of interest (R) years
• We need to find the rate of interest (R).

Formula for Simple Interest:

SI=P×R×T100SI=\frac{P\times R\times T}{100}SI=100P×R×T​

Since the time period TTT is equal to the rate of interest RRR, substitute T=RT=RT=R:

432=1200×R×R100432=\frac{1200\times R\times R}{100}432=1001200×R×R​

432=1200R2100432=\frac{1200R^2}{100}432=1001200R2​

432=12R2432=12R^2432=12R2

Solve for RRR:

R2=43212=36R^2=\frac{432}{12}=36R2=12432​=36

R=36=6R=\sqrt{36}=6R=36​=6

Final Answer:

The rate of interest is 6%. If you want, I can also help with similar problems or explain the concept of simple interest further!