the escape velocity from earth is approximately 11,186 m/s. if a space launch vehicle achieves an escape velocity of 10,000 m/s, what percentage of the escape velocity has been achieved?

The escape velocity from Earth is approximately 11.2 kilometers per second (km/s). This is the minimum speed an object must reach to break free from Earth's gravitational field without further propulsion, assuming no atmospheric resistance

. This value is derived from the formula:

ve=2GMRv_e=\sqrt{\frac{2GM}{R}}ve​=R2GM​​

where:

• GGG is the universal gravitational constant,
• MMM is the mass of the Earth,
• RRR is the radius of the Earth.

Using Earth's standard values, the calculation yields about 11.2 km/s (or 11,180 m/s)

. Thus, the commonly accepted approximate escape velocity from Earth's surface is 11.2 km/s.