Let's analyze the problem step by step.
Problem Restatement:
- Two jackets were bought at the same cost price (let's call it ₹xxx).
- One jacket was sold at a profit of 9%.
- The other jacket was sold at a profit of some percentage (which seems to be missing in your query).
- The difference in the selling prices of the two jackets is ₹1.
- We need to find the cost price of each jacket.
Given:
- Cost price of each jacket = ₹xxx
- Profit on first jacket = 9%
- Profit on second jacket = (missing from your query)
- Difference in selling prices = ₹1
Step 1: Define variables
Let the profit percentage on the second jacket be p%p%p%.
Step 2: Express selling prices
- Selling price of first jacket = x+9%x+9%x+9% of x=x+0.09x=1.09xx=x+0.09x=1.09xx=x+0.09x=1.09x
- Selling price of second jacket = x+p%x+p%x+p% of x=x+p100x=(1+p100)xx=x+\frac{p}{100}x=\left(1+\frac{p}{100}\right)xx=x+100px=(1+100p)x
Step 3: Use the difference in selling prices
The difference in selling prices is ₹1, so:
∣1.09x−(1+p100)x∣=1|1.09x-\left(1+\frac{p}{100}\right)x|=1∣1.09x−(1+100p)x∣=1
∣1.09x−(1+p100)x∣=1|1.09x-\left(1+\frac{p}{100}\right)x|=1∣1.09x−(1+100p)x∣=1
∣x(1.09−1−p100)∣=1|x(1.09-1-\frac{p}{100})|=1∣x(1.09−1−100p)∣=1
∣x(0.09−p100)∣=1|x(0.09-\frac{p}{100})|=1∣x(0.09−100p)∣=1
Step 4: Solve for xxx
x×∣0.09−p100∣=1x\times |0.09-\frac{p}{100}|=1x×∣0.09−100p∣=1
x=1∣0.09−p100∣x=\frac{1}{|0.09-\frac{p}{100}|}x=∣0.09−100p∣1
Conclusion:
To find the cost price xxx, we need the value of the profit percentage ppp on the second jacket.
Please provide the profit percentage on the second jacket so I can
calculate the exact cost price for you!
