The probability of getting a sum of 9 from two throws of a die is the number of favorable outcomes (combinations that add up to 9) divided by the total number of possible outcomes when throwing two dice. The favorable outcomes for sum 9 are: (3,6), (4,5), (5,4), and (6,3), which total 4 outcomes. Since each die has 6 faces, the total number of possible outcomes when throwing two dice is 6×6=366\times 6=366×6=36. Thus, the probability is:
436=19\frac{4}{36}=\frac{1}{9}364=91
So, the probability of getting a sum of 9 from two throws of a dice is 19\frac{1}{9}91 or about 0.1111 (11.11%).
