you are given the coordinates of a triangle and coordinates for only one of the vertices of its image under a translation. explain how to translate the entire triangle.

3 hours ago 3
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Certainly! Here's a clear explanation of how to translate the entire triangle when you have:

  • The coordinates of the original triangle's three vertices, and
  • The coordinates of only one vertex of the translated image.

How to Translate the Entire Triangle

Step 1: Identify the given points

  • Let the original triangle have vertices A(x1,y1)A(x_1,y_1)A(x1​,y1​), B(x2,y2)B(x_2,y_2)B(x2​,y2​), and C(x3,y3)C(x_3,y_3)C(x3​,y3​).
  • You are given the image of one vertex after translation, say A′(x1′,y1′)A'(x_1',y_1')A′(x1′​,y1′​).

Step 2: Find the translation vector

  • A translation moves every point by the same amount.
  • The translation vector v⃗\vec{v}v is the difference between the image vertex and the original vertex:

v⃗=(x1′−x1,y1′−y1)\vec{v}=(x_1'-x_1,\quad y_1'-y_1)v=(x1′​−x1​,y1′​−y1​)

  • This vector tells you how far and in what direction the triangle has moved.

Step 3: Apply the translation vector to the other vertices

  • To find the image of vertex BBB, add the translation vector to BBB:

B′=(x2+(x1′−x1),y2+(y1′−y1))B'=(x_2+(x_1'-x_1),\quad y_2+(y_1'-y_1))B′=(x2​+(x1′​−x1​),y2​+(y1′​−y1​))

  • Similarly, for vertex CCC:

C′=(x3+(x1′−x1),y3+(y1′−y1))C'=(x_3+(x_1'-x_1),\quad y_3+(y_1'-y_1))C′=(x3​+(x1′​−x1​),y3​+(y1′​−y1​))

Step 4: Write the coordinates of the translated triangle

  • The translated triangle has vertices A′(x1′,y1′)A'(x_1',y_1')A′(x1′​,y1′​), B′B'B′, and C′C'C′.

Summary

  • Find the translation vector by subtracting the original vertex coordinates from the translated vertex coordinates.
  • Add this vector to the other vertices of the original triangle.
  • The resulting points give you the coordinates of the entire translated triangle.

If you'd like, I can also provide a numerical example or help with a specific set of points!